20x^2-119x+176=0

Solution for 20x^2-119x+176=0 equation:

20x^2-119x+176=0

a = 20; b = -119; c = +176;
Δ = b2-4ac
Δ = -1192-4·20·176
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-119)-9}{2*20}=\frac{110}{40}
=2+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-119)+9}{2*20}=\frac{128}{40}
=3+1/5
$